There are mainly two types of R.C.C. footings:
1. One way reinforced footings.
2. Two way reinforced footings.
1. One Way Reinforced Footing: These footings are for the walls. In these footings main reinforcements are in the transverse direction of wall. In longitudinal directions there will be only nominal reinforcement.
2. Two Way Reinforced Footings: For columns two way reinforced footings are provided.
The following types of the footings are common:
(i) Isolated Column Footings: If separate footings are provided for each column, it is called isolated column footing. Figure 1 shows a typical isolated column footing. The size of footing is based on the area required to distribute the load of the columns safely over the soil . These footings are provided over a 100 to 150 mm bed concrete. Required reinforcements and thickness of footing are found by the design engineers. Thickness may be uniform or varying.
(ii) Combined Footings: Common footings may be provided for two columns. This type of footing is necessary when a column is very close to the boundary of the property and hence there is no scope to project footing much beyond the column face. Figure 2 shows a typical combined footing. The footing is to be designed for transferring loads from both columns safely to the soil. The two columns may or may not be connected by a strap beam.
(iii) Continuous Footings: If a footing is common to more than two columns in a row, it is called continuous footing. This type of footing is necessary, if the columns in a row are closer or if SBC of soil is low. Figure 3 shows this type of footing.
(iv) Mat Footing/Raft Footing: If the load on the column is quite high (Multistorey columns) or when the SBC of soil is low, the sizes of isolated columns may work out to be to such an extent that they overlap each other. In such situation a common footing may be provided to several columns as shown in Fig. 4 Such footings are known as raft footings. If the beams are provided in both directions over the footing slab for connecting columns, the raft foundations may be called as grid foundation also. The added advantage of such footing is, settlement is uniform and hence unnecessary stresses are not produced.
Builder's Engineer
Monday, December 2, 2019
Wednesday, November 27, 2019
CONVENTIONAL SPREAD FOOTINGS
This type of foundations are commonly used for walls and masonry columns. These foundations are built after opening the trenches to required depth. Such footings are economical up to a maximum depth of 3 m. As these foundations are suitable depth, they are grouped under shallow foundations.
Figure 1 shows a conventional spread footing for a wall and Fig. 2 shows it for a masonry column.
Before building these footing trenches are opened to required depth and the soil is rammed well. Then a plain concrete of mix 1 : 4 : 8 is provided. Its thickness varies from 150 to 200 mm. Over this bed, stone masonry footing is built. It is built in courses each course projecting 50 to 75 mm from the top course and height of each course being 150 to 200 mm. In case of wall footing the projections are only one direction while in case of columns, they are in both directions. The projection of bed concrete from the lowest course of foundation masonry is usually 150 mm.
Figure 1 shows a conventional spread footing for a wall and Fig. 2 shows it for a masonry column.
Before building these footing trenches are opened to required depth and the soil is rammed well. Then a plain concrete of mix 1 : 4 : 8 is provided. Its thickness varies from 150 to 200 mm. Over this bed, stone masonry footing is built. It is built in courses each course projecting 50 to 75 mm from the top course and height of each course being 150 to 200 mm. In case of wall footing the projections are only one direction while in case of columns, they are in both directions. The projection of bed concrete from the lowest course of foundation masonry is usually 150 mm.
Friday, September 6, 2019
Dimensions of Foundation
Guidelines for minimum dimensions are given below:
(a) Depth of Foundation: For all types of foundations minimum depth required is calculated
using Rankine’s Formula:

However in any case it is not less than 0.9 m. Finding safe bearing of the soil is an expert’s job,
and it is found after conducting tests in field or in Laboratories. However general values for common
soils are listed in Table 1.

(b) Width of Foundation: Width of wall foundations or size of column footing is determined by
first calculating the expected load and then dividing that with SBC. Thus,
(a) Depth of Foundation: For all types of foundations minimum depth required is calculated
using Rankine’s Formula:

However in any case it is not less than 0.9 m. Finding safe bearing of the soil is an expert’s job,
and it is found after conducting tests in field or in Laboratories. However general values for common
soils are listed in Table 1.

(b) Width of Foundation: Width of wall foundations or size of column footing is determined by
first calculating the expected load and then dividing that with SBC. Thus,
Friday, February 9, 2018
Plank floor
An alternative to the inverted T-beam is the pre-cast plank floor. These are reinforced lightweight concrete planks which sit side by side, supported as before by the internal leaf of blockwork. The planks are built into the blockwork at the sides as well as the ends and therefore restraint straps are not necessary in this instance.
Monday, September 25, 2017
Monday, September 11, 2017
Combined Rectangular Footing.
Fig. 3.14 shows a combined rectangular footing for two columns A and B carrying loads
W1 and W2, and spaced l centre to centre. If W' is the weight of the footing and qs is the safe bearing capacity, the footing area is given by
Suitable values of length L and breadth B of the footing are chosen, so that B x L = A. The longitudinal projections a1 and a2 should be so chosen that the C.G. of footing coincides with the C.G. of the two loads.
From the above, the projection a1 and a2 can be determined.
The net upward pressure p0 is given by
This net pressure intensity is used for structural analysis and design combined footing. A combined foundation may be either of reinforced cement concrete (R.C.C.) or of steel grillage type.
(i) Combined rectangular footing of R.C.C. A rectangular footing of R.C.C consists of a reinforced concrete slab which is designed for both longitudinal bending as well as transverse bending. If the distance between the columns. Typical details of a R.C. footing, without longitudinal beam, are shown in Fig. 3.15 Fig. 3.16 Shows typical details of rectangular footing, having longitudinal beam. The longitudinal beam may be provided either below the footing slab, or it may project above the slab.
(ii) Combined steel grillage rectangular footing. Such a footing is provided to support two steel stanchions.
The upper tier of steel joists receives the loads from the two columns and transfers the load to the lower tier. Fig. 3.17 shows typical details.
FIG. 3.14 COMBINED RECTANGULAR FOOTING.
W1 and W2, and spaced l centre to centre. If W' is the weight of the footing and qs is the safe bearing capacity, the footing area is given by
Suitable values of length L and breadth B of the footing are chosen, so that B x L = A. The longitudinal projections a1 and a2 should be so chosen that the C.G. of footing coincides with the C.G. of the two loads.
From the above, the projection a1 and a2 can be determined.
The net upward pressure p0 is given by
This net pressure intensity is used for structural analysis and design combined footing. A combined foundation may be either of reinforced cement concrete (R.C.C.) or of steel grillage type.
(i) Combined rectangular footing of R.C.C. A rectangular footing of R.C.C consists of a reinforced concrete slab which is designed for both longitudinal bending as well as transverse bending. If the distance between the columns. Typical details of a R.C. footing, without longitudinal beam, are shown in Fig. 3.15 Fig. 3.16 Shows typical details of rectangular footing, having longitudinal beam. The longitudinal beam may be provided either below the footing slab, or it may project above the slab.
(ii) Combined steel grillage rectangular footing. Such a footing is provided to support two steel stanchions.
The upper tier of steel joists receives the loads from the two columns and transfers the load to the lower tier. Fig. 3.17 shows typical details.
Monday, April 11, 2016
Structures: Folded Plate
The effect of folding on folded plates can be visualized with a sheet of paper. A flat paper deforms even under its own weight. Folding the paper adds strength and stiffness; yet under heavy load the folds may buckle. To secure the folds at both ends increases stability against buckling.
1. Flat paper deforms under its own weight
2. Folding paper increases strength and stiffness
3. Paper buckling under heavy load
4. Secured ends help resist buckling
1. Flat paper deforms under its own weight
2. Folding paper increases strength and stiffness
3. Paper buckling under heavy load
4. Secured ends help resist buckling
Friday, December 11, 2015
Vierendeels Configurations
Vierendeels may have various configurations, including one-way and two-way spans. One-way girders may be simply supported or continuous over more than two supports. They may be planar or prismatic with triangular or square profile for improved lateral load resistance. Some highway pedestrian bridges are of the latter type. A triangular cross-section has added stability, inherent in triangular geometry. It could be integrated with bands of skylights on top of girders.
When supports are provided on all sides, Vierendeel frames of two-way or three-way spans are possible options. They require less depth, can carry more load, have less deflection, and resist lateral load as well as gravity load. The two-way option is well suited for orthogonal plans; the three-way option adapts better to plans based on triangles, hexagons, or free-form variations thereof.
Moment resistant space frames for multi-story or high-rise buildings may be considered a special case of the Vierendeel concept.
1 One-way planar Vierendeel girder
2 One-way prismatic Vierendeel girder of triangular cross-section
3 One-way prismatic Vierendeel girder of square cross-section
4 Two-way Vierendeel space frame
5 Three-way Vierendeel space frame
6 Multi-story Vierendeel space frame
When supports are provided on all sides, Vierendeel frames of two-way or three-way spans are possible options. They require less depth, can carry more load, have less deflection, and resist lateral load as well as gravity load. The two-way option is well suited for orthogonal plans; the three-way option adapts better to plans based on triangles, hexagons, or free-form variations thereof.
Moment resistant space frames for multi-story or high-rise buildings may be considered a special case of the Vierendeel concept.
1 One-way planar Vierendeel girder
2 One-way prismatic Vierendeel girder of triangular cross-section
3 One-way prismatic Vierendeel girder of square cross-section
4 Two-way Vierendeel space frame
5 Three-way Vierendeel space frame
6 Multi-story Vierendeel space frame
Monday, November 30, 2015
Joist, Beam, Girder
Joists, beams, and girders can be arranged in three different configurations: joists supported by columns or walls1; joists supported by beams that are supported by columns2; and joists supported by beams, that are supported by girders, that are supported by columns3. The relationship between joist, beam, and girder can be either flush or layered framing. Flush framing, with top of joists, beams, and girders flush with each other, requires less structural depth but may require additional depth for mechanical systems. Layered framing allows the integration of mechanical systems. With main ducts running between beams and secondary ducts between joists. Further, flush framing for steel requires more complex joining, with joists welded or bolted into the side of beams to support gravity load. Layered framing with joists on top of beams with simple connection to prevent displacement only
2 Single layer framing: joists supported directly by walls
3 Double layer framing: joists supported by beams and beams by columns
4 Triple layer framing: joists supported by beams, beams by girders, and girders by columns
5 Flush framing: top of joists and beams line up May require additional depth for mechanical ducts
6 Layered framing: joists rest on top of beams Simpler and less costly framing May have main ducts between beams, secondary ducts between joists
A Joists
B Beam
C Girders
D Wall
E Column
F Pilaster
G Concrete slab on corrugated steel deck
2 Single layer framing: joists supported directly by walls
3 Double layer framing: joists supported by beams and beams by columns
4 Triple layer framing: joists supported by beams, beams by girders, and girders by columns
5 Flush framing: top of joists and beams line up May require additional depth for mechanical ducts
6 Layered framing: joists rest on top of beams Simpler and less costly framing May have main ducts between beams, secondary ducts between joists
A Joists
B Beam
C Girders
D Wall
E Column
F Pilaster
G Concrete slab on corrugated steel deck
Thursday, October 15, 2015
Gerber Beam
The Gerber beam is named after its inventor, Gerber, a German engineering professor at Munich. The Gerber beam has hinges at inflection points to reduce bending moments, takes advantage of continuity, and allows settlements without secondary stresses. The Gerber beam was developed in response to failures, caused by unequal foundation settlements in 19th century railroad bridges.
1. Simple beams over three spans
2. Reduced bending moment in continuous beam
3. Failure of continuous beam due to unequal foundation settlement, causing the span to double and the moment to increase four times
4. Gerber beam with hinges at inflection points minimizes bending moments and avoids failure due to unequal settlement
1. Simple beams over three spans
2. Reduced bending moment in continuous beam
3. Failure of continuous beam due to unequal foundation settlement, causing the span to double and the moment to increase four times
4. Gerber beam with hinges at inflection points minimizes bending moments and avoids failure due to unequal settlement
Monday, September 7, 2015
BEAM OPTIMIZATION
Optimizing long-span girders can save scares resources. The following are a few conceptual options to optimize girders. Optimization for a real project requires careful evaluation of alternate options, considering interdisciplinary aspects along with purely structural ones.
1 Moment diagram, stepped to reflect required resistance along girder
2 Steel girder with plates welded on top of flanges for increased resistance
3 Steel girder with plates welded below flanges for increased resistance
4 Reinforced concrete girder with reinforcing bars staggered as required
5 Girder of parabolic shape, following the bending moment distribution
1 Girder of tapered shape, approximating bending moment distribution
1 Moment diagram, stepped to reflect required resistance along girder
2 Steel girder with plates welded on top of flanges for increased resistance
3 Steel girder with plates welded below flanges for increased resistance
4 Reinforced concrete girder with reinforcing bars staggered as required
5 Girder of parabolic shape, following the bending moment distribution
1 Girder of tapered shape, approximating bending moment distribution
Tuesday, June 16, 2015
Structures: Bending, Effect of Overhang
Bending moments can be greatly reduced, using the effect of overhangs. This can be describe on the example of a beam but applies also to other bending members of horizontal, span subject to gravity load as well. For a beam subject to uniform load with two overhangs, a ratio of overhangs to mid-span of 1:2.8 (or about 1/3) is optimal, with equal positive and negative bending moments. This implies an efficient use of material because if the beam has a constant size – which is most common – the beam is used to full capacity on both, overhang and span. Compared to the same beam with supports at both ends, the bending moment in a beam with two overhangs is about one sixth ! To a lesser degree, a single overhang has a similar effect. Thus, taking advantage of overhangs in a design may result in great savings and economy of resources.
1. Simple beam with end supports and uniform load
2. Cantilevers of about 1/3 the span equalize positive and negative bending moments and reduces them to about one sixth, compared to a beam of equal length and load with but with simple end support.
1. Simple beam with end supports and uniform load
2. Cantilevers of about 1/3 the span equalize positive and negative bending moments and reduces them to about one sixth, compared to a beam of equal length and load with but with simple end support.
Thursday, April 23, 2015
Portal Method For Rough Moment Frame Design
The Portal Method for rough moment frame design is based on these assumptions:
• Lateral forces resisted by frame action
• Inflection points at mid-height of columns
• Inflection points at mid-span of beams
• Column shear is based on tributary area
• Overturn is resisted by exterior columns only
1. Single moment frame (portal)
2. Multistory moment frame
3. Column shear is total shear V distributed proportional to tributary area:
4. Column moment = column shear x height to inflection point
5. Exterior columns resist most overturn, the portal method assumes they resist all
6. Overturn moments per level are the sum of forces above the level times lever arm of each force to the column inflection point at the respective level:
7. Beam shear = column axial force below beam minus column axial force above beam Level 1 beam shear:
• Lateral forces resisted by frame action
• Inflection points at mid-height of columns
• Inflection points at mid-span of beams
• Column shear is based on tributary area
• Overturn is resisted by exterior columns only
1. Single moment frame (portal)
2. Multistory moment frame
3. Column shear is total shear V distributed proportional to tributary area:
4. Column moment = column shear x height to inflection point
5. Exterior columns resist most overturn, the portal method assumes they resist all
6. Overturn moments per level are the sum of forces above the level times lever arm of each force to the column inflection point at the respective level:
7. Beam shear = column axial force below beam minus column axial force above beam Level 1 beam shear:
Monday, March 16, 2015
ARCHITECTURAL STRUCTURES - GLOBAL MOMENT AND SHEAR
Global moments help to analyze not only a beam but also truss, cable or arch. They all resist global moments by a couple F times lever arm d:
The force F is expressed as T (tension) and C (compression) for beam or truss, and H (horizontal reaction) for suspension cable or arch, forces are always defined by the global moment and lever arm of resisting couple. For uniform load and simple support, the maximum moment M and maximum shear V are computed as:
For other load or support conditions use appropriate formulas
Beam
Beams resist the global moment by a force couple, with lever arm of 2/3 the beam depth d; resisted by top compression C and bottom tension T.
Truss
Trusses resist the global moment by a force couple and truss depth d as lever arm; with compression C in top chord and tension T in bottom chord. Global shear is resisted by vertical and / or diagonal web bars. Maximum moment at mid-span causes maximum chord forces. Maximum support shear causes maximum web bar forces.
Cable
Suspension cables resist the global moment by horizontal reaction with sag f as lever arm. The horizontal reaction H, vertical reaction R, and maximum cable tension T form an equilibrium vector triangle; hence the maximum cable tension is:
Arch
Arches resist the global moment like a cable, but in compression instead of tension:
However, unlike cables, arches don’t adjust their form for changing loads; hence, they assume bending under non-uniform load as product of funicular force and lever arm between funicular line and arch form (bending stress is substituted by conservative axial stress for approximate schematic design).
The force F is expressed as T (tension) and C (compression) for beam or truss, and H (horizontal reaction) for suspension cable or arch, forces are always defined by the global moment and lever arm of resisting couple. For uniform load and simple support, the maximum moment M and maximum shear V are computed as:
For other load or support conditions use appropriate formulas
Beam
Beams resist the global moment by a force couple, with lever arm of 2/3 the beam depth d; resisted by top compression C and bottom tension T.
Truss
Trusses resist the global moment by a force couple and truss depth d as lever arm; with compression C in top chord and tension T in bottom chord. Global shear is resisted by vertical and / or diagonal web bars. Maximum moment at mid-span causes maximum chord forces. Maximum support shear causes maximum web bar forces.
Cable
Suspension cables resist the global moment by horizontal reaction with sag f as lever arm. The horizontal reaction H, vertical reaction R, and maximum cable tension T form an equilibrium vector triangle; hence the maximum cable tension is:
Arch
Arches resist the global moment like a cable, but in compression instead of tension:
However, unlike cables, arches don’t adjust their form for changing loads; hence, they assume bending under non-uniform load as product of funicular force and lever arm between funicular line and arch form (bending stress is substituted by conservative axial stress for approximate schematic design).
Monday, March 2, 2015
Seismic Design, Eccentricity
Offset between center of mass and center of resistance causes eccentricity which causes torsion under seismic load. The plans at left identify concentric and eccentric conditions:
1 X-direction concentric
Y-direction eccentric
2 X-direction eccentric
Y-direction eccentric
3 X-direction concentric
Y-direction concentric
4 X-direction concentric
Y-direction concentric
5 X-direction concentric
Y-direction concentric
6 X-direction concentric
Y-direction concentric
Note: Plan 5 provides greater resistance against torsion than plan 6 due to wider wall spacing Plan 6 provides greater bending resistance because walls act together as core and thus provide a greater moment of inertia.
1 X-direction concentric
Y-direction eccentric
2 X-direction eccentric
Y-direction eccentric
3 X-direction concentric
Y-direction concentric
4 X-direction concentric
Y-direction concentric
5 X-direction concentric
Y-direction concentric
6 X-direction concentric
Y-direction concentric
Note: Plan 5 provides greater resistance against torsion than plan 6 due to wider wall spacing Plan 6 provides greater bending resistance because walls act together as core and thus provide a greater moment of inertia.
Thursday, February 12, 2015
Structures - Horizontal Floor and Roof Diaphragms
Horizontal floor and roof diaphragms transfer lateral load to walls and other supporting elements. The amount each wall assumes depends if diaphragms are flexible or rigid.
1. Flexible diaphragm
Floors and roofs with plywood sheathing are usually flexible; they transfer load, similar to simple beams, in proportion to the tributary area of each wall. Wall reactions R are computed based on tributary area of each wall. Required shear flow q (wall capacity)
2. Rigid diaphragm
Concrete slabs and some steel decks are rigid; they transfer load in proportion to the relative stiffness of each wall. Since rigid diaphragms experience only minor deflections under load they impose equal drift on walls of equal length and stiffness. For unequal walls reactions are proportional to a resistance factor r.
1. Flexible diaphragm
Floors and roofs with plywood sheathing are usually flexible; they transfer load, similar to simple beams, in proportion to the tributary area of each wall. Wall reactions R are computed based on tributary area of each wall. Required shear flow q (wall capacity)
2. Rigid diaphragm
Concrete slabs and some steel decks are rigid; they transfer load in proportion to the relative stiffness of each wall. Since rigid diaphragms experience only minor deflections under load they impose equal drift on walls of equal length and stiffness. For unequal walls reactions are proportional to a resistance factor r.
Wednesday, January 28, 2015
Structures - Design Response Spectrum
The IBC Design Response Spectrum correlate time period T and Spectral Acceleration, defining three zones. Two critical zones are:
T < TS governs low-rise structures of short periods
T > TS governs tall structures of long periods
where
T = time period of structure (T ~ 0.1 sec. per story - or per ASCE 7 table 1615.1.1)
TS = SDS/SD1 (See the following graphs for SDS and SD1)
T < TS governs low-rise structures of short periods
T > TS governs tall structures of long periods
where
T = time period of structure (T ~ 0.1 sec. per story - or per ASCE 7 table 1615.1.1)
TS = SDS/SD1 (See the following graphs for SDS and SD1)
Wednesday, January 7, 2015
Seismic Design
Earthquakes are caused primarily by release of shear stress in seismic faults, such as the San Andreas fault, that separates the Pacific plate from the North American plate, two of the plates that make up the earth’s crust according to the plate tectonics theory. Plates move with respect to each other at rates of about 2-5 cm per year, building up stress in the process. When stress exceeds the soil’s shear capacity, the plates slip and cause earthquakes. The point of slippage is called the hypocenter or focus, the point on the surface above is called the epicenter. Ground waves propagate in radial pattern from the focus. The radial waves cause shaking somewhat more vertical above the focus and more horizontal far away; yet irregular rock formations may deflect the ground waves in random patterns. The Northridge earthquake of January 17, 1994 caused unusually strong vertical acceleration because it occurred under the city.
Occasionally earthquakes may occur within plates rather than at the edges. This was the case with a series of strong earthquakes in New Madrid, along the Mississippi River in Missouri in 1811-1812. Earthquakes are also caused by volcanic eruptions, underground explosions, or similar man-made events.
Buildings are shaken by ground waves, but their inertia tends to resists the movement which causes lateral forces. The building mass (dead weight) and acceleration effects these forces. In response, structure height and stiffness, as well as soil type effect the response of buildings to the acceleration. For example, seismic forces for concrete shear walls (which are very stiff) are considered twice that of more flexible moment frames. As an analogy, the resilience of grass blades will prevent them from breaking in an earthquake; but when frozen in winter they would break because of increased stiffness.
The cyclical nature of earthquakes causes dynamic forces that are best determined by dynamic analysis. However, given the complexity of dynamic analysis, many buildings of regular shape and height limits, as defined by codes, may be analyzed by a static force method, adapted from Newton’s law F= ma (Force = mass x acceleration).
1 Seismic wave propagation and fault rupture
2 Lateral slip fault
3 Thrust fault
4 Building overturn
5 Building shear
6 Bending of building (first mode)
7 Bending of building (higher mode)
E Epicenter
H Hypocenter
Occasionally earthquakes may occur within plates rather than at the edges. This was the case with a series of strong earthquakes in New Madrid, along the Mississippi River in Missouri in 1811-1812. Earthquakes are also caused by volcanic eruptions, underground explosions, or similar man-made events.
Buildings are shaken by ground waves, but their inertia tends to resists the movement which causes lateral forces. The building mass (dead weight) and acceleration effects these forces. In response, structure height and stiffness, as well as soil type effect the response of buildings to the acceleration. For example, seismic forces for concrete shear walls (which are very stiff) are considered twice that of more flexible moment frames. As an analogy, the resilience of grass blades will prevent them from breaking in an earthquake; but when frozen in winter they would break because of increased stiffness.
The cyclical nature of earthquakes causes dynamic forces that are best determined by dynamic analysis. However, given the complexity of dynamic analysis, many buildings of regular shape and height limits, as defined by codes, may be analyzed by a static force method, adapted from Newton’s law F= ma (Force = mass x acceleration).
1 Seismic wave propagation and fault rupture
2 Lateral slip fault
3 Thrust fault
4 Building overturn
5 Building shear
6 Bending of building (first mode)
7 Bending of building (higher mode)
E Epicenter
H Hypocenter
Tuesday, December 2, 2014
Wind effect - Structural Design
A building in the path of wind causes wind pressure which in turn causes force, shear, and overturn moment at each level that must be resisted, following a load path to the foundations (wind wall pressure transfers to horizontal diaphragms, then to shear walls, finally to foundation). Wind pressure times tributary area per level causes lateral force per level. Shear per level, the sum of wind forces above, defines required resistance. Overturn moment per level is the sum of forces above times their height above the respective level.
1 Wind force, shear, and overturn moment per level
Fx = wind force = wind pressure times tributary area per level exposed to wind
VX = shear per level = sum of Fx above
Mx = overturn moment = sum of all forces above times their distance above level x.
2 Overturn effect
3 Windward pressure increase with height
4 Wind force
Fx = (windward pressure + leeward suction) times tributary area per level
(leeward wind suction is assumed constant for full height)
Fx = P A
P = wind pressure and suction in psf (Pa)
A = tributary area exposed to wind
(tributary area = building width times half the story height above and below)
5 Shear
Wind shear per level = sum of all wind forces above
Wind shear is the integration of wind forces above
6 Overturn moment
Overturn moment per level = sum of all forces above times their distance
Overturn moment per level = integration of shear diagram above respective level
1 Wind force, shear, and overturn moment per level
Fx = wind force = wind pressure times tributary area per level exposed to wind
VX = shear per level = sum of Fx above
Mx = overturn moment = sum of all forces above times their distance above level x.
2 Overturn effect
3 Windward pressure increase with height
4 Wind force
Fx = (windward pressure + leeward suction) times tributary area per level
(leeward wind suction is assumed constant for full height)
Fx = P A
P = wind pressure and suction in psf (Pa)
A = tributary area exposed to wind
(tributary area = building width times half the story height above and below)
5 Shear
Wind shear per level = sum of all wind forces above
Wind shear is the integration of wind forces above
6 Overturn moment
Overturn moment per level = sum of all forces above times their distance
Overturn moment per level = integration of shear diagram above respective level
Tuesday, November 18, 2014
Wind Load - Structural Design
1 Wind load on gabled building
2 Wind load on dome or vault
3 Protected buildings inside a city
4 Exposed tall building inside a city
5 Wind flow around and above exposed building
6 Wind speed amplified by building configuration
Wind channeled between buildings causes a Venturi effect of increased wind speed. Air movement through buildings causes internal pressure that effects curtain walls and cladding design. Internal pressure has a balloon-like effect, acting outward if the wind enters primarily on the windward side. Openings on leeward or side walls cause inward pressure. In tall buildings with fixed curtain wall the difference between outside wind pressure and interior pressure causes air movement from high pressure to low pressure.
This causes air infiltration on the windward side and outflow on the leeward side. In high-rise buildings, warm air moving from lower to upper levels causes pressures at top levels on the leeward face and negative suction on lower levels. Wind pressure is based on the equation developed by Daniel Bernoulli (1700-1782). For steady air flow of velocity V, the velocity pressure, q, on a rigid body is
q = pV^2 / 2
p = air density (air weight divided by the acceleration of gravity g = 32.2 ft/sec2)
Air of 15°C at sea level weighs 0.0765 Ib/ft
3, which yields:
q = 0.00256V^2 (q in psf)
The American National Standards Institute (ANSI) Minimum design loads for buildings and other structures (ANSI A58.1 - 1982), converted dynamic pressure to velocity pressure qz (psf) at height z as
2 Wind load on dome or vault
3 Protected buildings inside a city
4 Exposed tall building inside a city
5 Wind flow around and above exposed building
6 Wind speed amplified by building configuration
Wind channeled between buildings causes a Venturi effect of increased wind speed. Air movement through buildings causes internal pressure that effects curtain walls and cladding design. Internal pressure has a balloon-like effect, acting outward if the wind enters primarily on the windward side. Openings on leeward or side walls cause inward pressure. In tall buildings with fixed curtain wall the difference between outside wind pressure and interior pressure causes air movement from high pressure to low pressure.
This causes air infiltration on the windward side and outflow on the leeward side. In high-rise buildings, warm air moving from lower to upper levels causes pressures at top levels on the leeward face and negative suction on lower levels. Wind pressure is based on the equation developed by Daniel Bernoulli (1700-1782). For steady air flow of velocity V, the velocity pressure, q, on a rigid body is
q = pV^2 / 2
p = air density (air weight divided by the acceleration of gravity g = 32.2 ft/sec2)
Air of 15°C at sea level weighs 0.0765 Ib/ft
3, which yields:
q = 0.00256V^2 (q in psf)
The American National Standards Institute (ANSI) Minimum design loads for buildings and other structures (ANSI A58.1 - 1982), converted dynamic pressure to velocity pressure qz (psf) at height z as
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