Tuesday, February 19, 2013

Slip Circle Example.

Slip circles have been mentioned previously and the following example, showing the calculation process for
deriving the factor of safety for a single slip circle with an arbitrarily selected radius, is included here for com-
pleteness. In order to find the most critical condition, i.e. the minimum factor of safety, a number of slip circle  calculations should be carried out using different radii. The engineer experienced in this field is able to identify the most likely mode of failure based on a knowledge of soil parameters and boundary conditions and hence reduce the computational effort required. This iterative calculation process is time-consuming and can be more cost-effectively carried out by one of the commercial software packages for slip circle analysis that are available.

A detached house, 9 m × 9 m on plan, is to be constructed on a sloping site; a section through the proposal is as shown  in Fig. 15.10.

Slip circle design example.
Fig. 15.10 Slip circle design example.

Assuming an average value of  cu = 50 kN/m2, consider  a one metre wide strip for the case where Øu  = 0, i.e. the undrained condition immediately following construction

Next set up a circular arc using compasses, to pass through the edge of the excavation for the basement of slab/footing and close to the bottom of the new embankment. Measure the radius, and compute the arc length, r = 12.5 m. The angle subtended by the arc =α= 90°. Therefore

Deduct a length (arbitrary) disturbed by excavation and subsequent filling, i.e. 19.6 − 3.6 = 16 m.

Weight of ground is F1, assuming the small area of fill above the chord line equals the area omitted within the house.

Using 16 kN/m3 for existing ground and compacted fill
weight, F1 = 45 × 16 = 720 kN/m

The weight of a detached house of two storeys, including external and internal load-bearing walls, when averaged per metre run, equates to 170 kN/m. Therefore

By simple geometry, the centroids of the areas are located, and scaling their lever arms

Combining these gives

    2304 + 680 − 194 = 2790 kNm


Since 3.6 is greater than 2, the factor of safety commonly adopted for slope failures involving buildings, then there  is an adequate factor of safety against slip circle failure.

However, as mentioned above, other circles should be checked in order to find the critical case.

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